Numerical 3-dimensional matching

Numerical 3-dimensional matching is an NP-complete decision problem. It is given by three multisets of integers X {\displaystyle X} , Y {\displaystyle Y} and Z {\displaystyle Z} , each containing k {\displaystyle k} elements, and a bound b {\displaystyle b} . The goal is to select a subset M {\displaystyle M} of X × Y × Z {\displaystyle X\times Y\times Z} such that every integer in X {\displaystyle X} , Y {\displaystyle Y} and Z {\displaystyle Z} occurs exactly once and that for every triple ( x , y , z ) {\displaystyle (x,y,z)} in the subset x + y + z = b {\displaystyle x+y+z=b} holds. This problem is labeled as [SP16] in.[1]

Example

Take X = { 3 , 4 , 4 } {\displaystyle X=\{3,4,4\}} , Y = { 1 , 4 , 6 } {\displaystyle Y=\{1,4,6\}} and Z = { 1 , 2 , 5 } {\displaystyle Z=\{1,2,5\}} , and b = 10 {\displaystyle b=10} . This instance has a solution, namely { ( 3 , 6 , 1 ) , ( 4 , 4 , 2 ) , ( 4 , 1 , 5 ) } {\displaystyle \{(3,6,1),(4,4,2),(4,1,5)\}} . Note that each triple sums to b = 10 {\displaystyle b=10} . The set { ( 3 , 6 , 1 ) , ( 3 , 4 , 2 ) , ( 4 , 1 , 5 ) } {\displaystyle \{(3,6,1),(3,4,2),(4,1,5)\}} is not a solution for several reasons: not every number is used (a 4 X {\displaystyle 4\in X} is missing), a number is used too often (the 3 X {\displaystyle 3\in X} ) and not every triple sums to b {\displaystyle b} (since 3 + 4 + 2 = 9 b = 10 {\displaystyle 3+4+2=9\neq b=10} ). However, there is at least one solution to this problem, which is the property we are interested in with decision problems. If we would take b = 11 {\displaystyle b=11} for the same X {\displaystyle X} , Y {\displaystyle Y} and Z {\displaystyle Z} , this problem would have no solution (all numbers sum to 30 {\displaystyle 30} , which is not equal to k b = 33 {\displaystyle k\cdot b=33} in this case).

Every instance of the Numerical 3-dimensional matching problem is an instance of both the 3-partition problem, and the 3-dimensional matching problem.

Given an instance of numeric 3d-matching , construct a tripartite hypergraph with sides X {\displaystyle X} , Y {\displaystyle Y} and Z {\displaystyle Z} , where there is an hyperedge ( x , y , z ) {\displaystyle (x,y,z)} if and only if x + y + z = T {\displaystyle x+y+z=T} . A matching in this hypergraph corresponds to a solution to ABC-partition.

Proof of NP-completeness

The numerical 3-d matching problem is problem [SP16] of Garey and Johnson.[1] They claim it is NP-complete, and refer to,[2] but the claim is not proved at that source. The NP-hardness of the related problem 3-partition is done in [1] by a reduction from 3-dimensional matching via 4-partition. To prove NP-completeness of the numerical 3-dimensional matching, the proof should be similar, but a reduction from 3-dimensional matching via the numerical 4-dimensional matching problem should be used. Explicit proofs of NP-hardness are given in later papers:

  • Yu, Hoogeveen and Lenstra[3] prove NP-hardness of a very restricted version of Numerical 3-Dimensional Matching, in which two of the three sets contain only the numbers 1,...,k.
  • Caracciolo, Fichera, and Sportiello[4] prove NP-hardness of Numerical 3-Dimensional Matching and related problems by reduction from NAE-SAT. The reduction is linear, that is, the size of the reduced instance is a linear function of the size of the original instance.

References

  1. ^ a b c Garey, Michael R. and David S. Johnson (1979), Computers and Intractability; A Guide to the Theory of NP-Completeness. ISBN 0-7167-1045-5
  2. ^ Garey, M. R.; Johnson, D. S. (December 1975). "Complexity Results for Multiprocessor Scheduling under Resource Constraints". SIAM Journal on Computing. 4 (4): 397–411. doi:10.1137/0204035. ISSN 0097-5397.
  3. ^ Yu, Wenci; Hoogeveen, Han; Lenstra, Jan Karel (2004-09-01). "Minimizing Makespan in a Two-Machine Flow Shop with Delays and Unit-Time Operations is NP-Hard". Journal of Scheduling. 7 (5): 333–348. doi:10.1023/B:JOSH.0000036858.59787.c2. ISSN 1099-1425.
  4. ^ Caracciolo, Sergio; Fichera, Davide; Sportiello, Andrea (2006-04-28), One-in-Two-Matching Problem is NP-complete, arXiv:cs/0604113, Bibcode:2006cs........4113C